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-2.85z^2+8.04z+5.58=8.94z+.51z^2-3.56
We move all terms to the left:
-2.85z^2+8.04z+5.58-(8.94z+.51z^2-3.56)=0
We get rid of parentheses
-2.85z^2-.51z^2-8.94z+8.04z+3.56+5.58=0
We add all the numbers together, and all the variables
-3.36z^2-0.9z+9.14=0
a = -3.36; b = -0.9; c = +9.14;
Δ = b2-4ac
Δ = -0.92-4·(-3.36)·9.14
Δ = 123.6516
The delta value is higher than zero, so the equation has two solutions
We use following formulas to calculate our solutions:$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}$$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}$$z_{1}=\frac{-b-\sqrt{\Delta}}{2a}=\frac{-(-0.9)-\sqrt{123.6516}}{2*-3.36}=\frac{0.9-\sqrt{123.6516}}{-6.72} $$z_{2}=\frac{-b+\sqrt{\Delta}}{2a}=\frac{-(-0.9)+\sqrt{123.6516}}{2*-3.36}=\frac{0.9+\sqrt{123.6516}}{-6.72} $
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